Aggregate

ANY_VALUE

MySQL

Mengembalikan salah satu nilai dari grup tanpa menentukan mana yang dipilih. Berguna untuk menghindari error ONLY_FULL_GROUP_BY.

Tipe hasil: Same as input typeDiperbarui: 7 Jan 2026

Syntax

SQL

ANY_VALUE(expr)

Parameter

expranywajib

Ekspresi yang akan diambil salah satu nilainya

Contoh Penggunaan

Menghindari ONLY_FULL_GROUP_BY Error

SQL

1 SELECT department_id,
2        ANY_VALUE(department_name) AS dept_name,
3        COUNT(*) AS emp_count
4 FROM employees
5 GROUP BY department_id;

Mengambil nama departemen tanpa memasukkannya ke GROUP BY.

Hasil

dept_id: 1, dept_name: Sales, emp_count: 25

ANY_VALUE dengan Subquery

SQL

1 SELECT user_id,
2        ANY_VALUE(username) AS username,
3        SUM(order_total) AS total_spent
4 FROM orders o
5 JOIN users u ON o.user_id = u.id
6 GROUP BY user_id;

Mengambil username dari join tanpa GROUP BY.

Hasil

user_id: 1, username: john_doe, total_spent: 1500

Kolom dengan Nilai Sama

SQL

1 SELECT order_id,
2        ANY_VALUE(customer_name) AS customer,
3        COUNT(*) AS item_count
4 FROM order_items oi
5 JOIN orders o ON oi.order_id = o.id
6 GROUP BY order_id;

Customer name sama untuk semua item dalam order yang sama.

Hasil

order_id: 100, customer: Alice, item_count: 5

Fungsi Equivalen di Database Lain

ANY_VALUE

BigQuery

ANY_VALUE

DuckDB

Kembali ke MySQL Functions

1	SELECT department_id,
2	ANY_VALUE(department_name) AS dept_name,
3	COUNT(*) AS emp_count
4	FROM employees
5	GROUP BY department_id;

1	SELECT user_id,
2	ANY_VALUE(username) AS username,
3	SUM(order_total) AS total_spent
4	FROM orders o
5	JOIN users u ON o.user_id = u.id
6	GROUP BY user_id;

1	SELECT order_id,
2	ANY_VALUE(customer_name) AS customer,
3	COUNT(*) AS item_count
4	FROM order_items oi
5	JOIN orders o ON oi.order_id = o.id
6	GROUP BY order_id;